Determination of PH of the Acid Solution

Sample Question: Take some Ethanol and Oxidizes Ethanol in presence of KMnO₄ and produce 0.01 M axid. The acid react with strong base and produce 0.01 M salt. The dissociation constant of acid is 1.8 x 10^-5.

According to question,

[Salt] = 0.01 M

[Acid] = 0.01 M

Ka = 1.8 x 10^-5

Pka = — log (1.8 x 10^-5) = 4.82

We know, p^H = pka + log [Salt/Acid]

= 4.82 + log [0.01/0.01]

= 4.82 + log l = 4.82 [Ans.]